我有一个 wordpress 端点，我有一些 json 数据。不幸的是，我不知道如何在函数中返回这个 json 数据。我试过 json_decode 但它没有返回任何东西。然后端点工作。如果我使用 json_encode 它返回数据，但还包括换行符和其他内容。问题似乎出在语法上，因为它已经是我所拥有的完整的 json 了。我怎样才能返回已经在 json 语法中的东西？
add_action('wp_ajax_nopriv_inboundCall', 'testFunction');
add_action('wp_ajax_inboundCall', 'testFunction');
function testFunction() {
echo json_decode('{
"testData": [
{
"_id": "1",
"name": "testName1"
},
{
"_id": "2",
"name": "testName2"
},
],
"testState": {
"1": [
1,
0
"2": [
1,
0
]
}
}');
die();
}回答1
function testFunction() {
return json_decode('{
"testData": [
{
"_id": "1",
"name": "testName1"
},
{
"_id": "2",
"name": "testName2"
},
],
"testState": {
"1": [
1,
0
"2": [
1,
0
]
}
}'); }回答2
我将 json_decode 的输出保存到一个变量，然后在该变量上运行 json_encode。现在它似乎工作了。
function inboundCall() {
$json = json_decode('{
"topics": [
{
"_id": "1",
"name": "davisio",
"crdate": "2022-01-17T12:40:03.430Z",
"modified": "2022-01-17T12:40:03.430Z"
},
{
"_id": "2",
"name": "LoRaWAN",
"crdate": "2022-01-17T12:40:33.848Z",
"modified": "2022-01-17T12:40:33.848Z"
},
{
"_id": "3",
"name": "Kommunale Beziehungen",
"crdate": "2022-01-19T15:17:10.094Z",
"modified": "2022-01-19T15:17:10.094Z"
},
{
"_id": "4",
"name": "Test",
"crdate": "2022-03-31T13:29:41.799Z",
"modified": "2022-03-31T13:29:41.799Z"
}
],
"serviceState": {
"1": [
1,
0,
0,
1,
0,
0,
0,
1
],
"2": [
1,
0,
0,
0,
0,
0,
0,
1
],
"4": [
1,
0,
0,
0,
0,
0,
0,
1
]
}
}');
echo json_encode($json);
die();
}