下面是我要解析的 xml。

<url>
   <loc>https://www.houseofindya.com/aqua-chanderi-pleated-sharara-pants-177/iprdt</loc>
   <image:image>
      <image:loc>https://img.faballey.com/Images/Product/IPL00325Z/d3.jpg</image:loc>
      <image:title>Green Chanderi Pleated Sharara Pants</image:title>
   </image:image>
   <priority>0.8</priority>
   <changefreq>daily</changefreq>
</url>
<url>
   <loc>https://www.houseofindya.com/aqua-foil-chanderi-kurta-171/iprdt</loc>
   <image:image>
      <image:loc>https://img.faballey.com/Images/Product/ITN01710Z/d3.jpg</image:loc>
      <image:title>Aqua Foil Chanderi Kurta</image:title>
   </image:image>
   <priority>0.8</priority>
   <changefreq>daily</changefreq>
</url>

我只需要获取 <loc> 标签的文本。因此，我执行以下操作：-

soup = BeautifulSoup(xml, features='xml')
loc = soup.find('loc')
while loc is not None:
    url = loc.text
    yield url
    loc = loc.find_next('loc')

我得到的结果是

1. https://www.houseofindya.com/aqua-chanderi-pleated-sharara-pants-177/iprdt
2. https://img.faballey.com/Images/Product/IPL00325Z/d3.jpg
3. https://www.houseofindya.com/aqua-foil-chanderi-kurta-171/iprdt
4. https://img.faballey.com/Images/Product/ITN01710Z/d3.jpg

但是，我想要的只是 https://www.houseofindya.com/aqua-chanderi-pleated-sharara-pants-177/iprdt 和 https://www.houseofindya.com/aqua-foil-chanderi-kurta-171/iprdt。我不想要 <image:loc> 的文本。

我在这里想念什么？

from bs4 import BeautifulSoup

xml_doc = """
... your XML from question here ...
"""

soup = BeautifulSoup(xml_doc, "html.parser")

for loc in soup.select("url > loc"):
    print(loc.text)

https://www.houseofindya.com/aqua-chanderi-pleated-sharara-pants-177/iprdt
https://www.houseofindya.com/aqua-foil-chanderi-kurta-171/iprdt