编辑：一旦我反序列化了这些信息，我怎样才能访问我需要的数据？我需要获取的唯一信息是每个附件的 TransitTime 和 Cost。
我正在使用一个 API，其中我需要来自嵌套对象的数据，但我不确定如何访问这些信息。我已将数据传递给 API，并根据数据从 API 返回的方式设置了新类。
这是响应的样子：
{"RatingResponse":
{"Success":"true",
"Message":"",
"QuoteID":"57450",
"LoadNum":"57450",
"Rates":{
"Rate":[
{"SCAC":"TEST",
"CarrierName":"TEST",
"TransitTime":"1",
"ServiceLevel":"D",
"TotalCost":"983.69",
"ThirdPartyCharge":"983.69",
"Accessorials":{
"Accessorial":[
{"Code":"400",
"Cost":"1,655.55",
"Description":"Freight"
},
{"Code":"DSC",
"Cost":"-985.55",
"Description":"Discount"
},
{"Code":"FUE",
"Cost":"313.69",
"Description":"Fuel Surcharge"
}
]
},
"QuoteNumber":""
},
{"SCAC":"TEST2",
"CarrierName":"TEST2",
"TransitTime":"1",
"ServiceLevel":"D",
"TotalCost":"983.69",
"ThirdPartyCharge":"983.69",
"Accessorials":{
"Accessorial":[
{"Code":"400",
"Cost":"1,655.55",
"Description":"Freight"
},
{"Code":"DSC",
"Cost":"-985.55",
"Description":"Discount"
},
{"Code":"FUE",
"Cost":"313.69",
"Description":"Fuel Surcharge"
}
]
},
"QuoteNumber":""
}
]
},
"AverageTotalCost":"983.69"
}}
我已将其转换为 C#：
public class Accessorial
{
public string Code;
public string Cost;
public string Description;
}
public class Accessorials
{
public List<Accessorial> Accessorial;
}
public class Rate
{
public string SCAC;
public string CarrierName;
public string TransitTime;
public string ServiceLevel;
public string TotalCost;
public string ThirdPartyCharge;
public Accessorials Accessorials;
public string QuoteNumber;
}
public class Rates
{
public List<Rate> Rate;
}
public class RatingResponse
{
public string Success;
public string Message;
public string QuoteID;
public string LoadNum;
public Rates Rates;
public string AverageTotalCost;
}
public class Root
{
public RatingResponse RatingResponse;
}我需要的唯一 values 是费率运输时间和服务水平以及辅助成本。我是 API 的初学者，不知道如何只返回这些信息。任何帮助是极大的赞赏！
回答1
如果您使用此代码，则不需要任何课程
var rate = (JArray)JObject.Parse(json)["RatingResponse"]["Rates"]["Rate"];
var result = rate.Select(r => new
{
TransitTime = (int)r["TransitTime"],
ServiceLevel = (string) r["ServiceLevel"],
AccessorialCost = ((JArray)r["Accessorials"]["Accessorial"]).Select(r => (double)r["Cost"]).ToList()
});结果（json格式）
[
{
"TransitTime": 1,
"ServiceLevel": "D",
"AccessorialCost": [
1655.55,
-985.55,
313.69
]
},
{
"TransitTime": 1,
"ServiceLevel": "D",
"AccessorialCost": [
1655.55,
-985.55,
313.69
]
}
]或者您可以创建一个数据类而不是匿名的
List<Data> result = rate.Select(r => new Data
{
....
}).ToList();
public class Data
{
public int TransitTime { get; set; }
public string ServiceLevel { get; set; }
public List<double> AccessorialCost { get; set; }
}回答2
我喜欢@Serge 的回答，但我更喜欢在课堂上取得成绩，因为“我只需要......”永远不会持续很长时间，对吗？下面是关于将 JSON 加载到 https://stackoverflow.com/questions/48585029/deserialize-multiple-json-into-object-c-sharp 的一个很好的讨论：您的 JSON 在 JSON2C#.com 中出错，但本质上您的根对象需要其他类。就像是
public class Root
{
public RatingResponse RatingResponse;
public Rates Rates;
public Accessorials Accessorials;
}然后反序列化为您的复杂对象
JsonConvert.DeserializeObject<RootObject>(json)我正在做这件事，所以请原谅任何语法错误。